Question

.determinati numerele intregi consecutive x y si z in urmatoarele cazuri stiind ca:
a. x:(y-z)= - 59
b.x:(y-z)= -71
c. x:(z-y)= -36
va rog urgent​

Answer 1

Răspuns:

Explicație pas cu pas:

x, y si z sunt trei numere întregi consecutive

y = x - 1; z = x + 1

a)

$x:(y-z)= - 59 \iff x:[x-1-(x+1)]= - 59 \iff x:(x-1-x-1)= - 59 \iff x:(-2)= - 59 \iff x = (-2)(-59) \implies x = 118 \implies y = 117 \implies z = 119$

b)

$x:(y-z)= - 71 \iff x:[x-1-(x+1)]= - 71 \iff x:(x-1-x-1)= - 71 \iff x:(-2)= - 71 \iff x = (-2)(-71) \implies x = 142 \implies y = 141 \implies z = 143$

c)

$x:(z-y)= - 36 \iff x:[x+1-(x-1)]= - 36 \iff x:(x+1-x+1)= - 36 \iff x:2= - 36 \iff x = 2 \cdot (-36) \implies x = -72 \implies y = -73 \implies z = -71$