Question

Determinati numerele nat. a,b,c,stiind ca: a+b=100,b+c=110,a+c=90

Answer 1

(a+b)+(b+c)+(a+c)=100+110+90
2a+2b+2c=300
a+b+c=150
a=(a+b+c)-(b+c)
a=150-110=40
b=(a+b)-a
b=100-40=60
c=(a+c)-a
c=90-40=50
Deci a=40, b=60, c=50

Answer 2

(a+b)+(b+c)+(a+c)=100+110+90
2a+2b+2c=300
a=150-110=40
b=100-40=60
c=(a+c)-a
c=90-40=50
a=40
b=60
c=50