Question

Determinati numerele naturale ,,a,,  ,,b,,  ,,c,, consecutive, stiind ca primul micsorat cu 6 face cu 6 mai mult decat jumatatea celui de-al doilea.

Answer 1

[tex]a,b,c~consecutive \\ b=a+1 \\ c=a+2 \\ a-6= \frac{b}{2}+6 \\ a-6= \frac{a+1}{2}+6 \\ ^{2)}a= \frac{a+1}{2}+^{2)}12 \\ \frac{2a}{2}= \frac{a+1}{2}+ \frac{24}{2}|*2 \\ 2a=a+25 \\ \boxed{a=25} \\ \boxed{b=26} \\ \boxed{c=27} [/tex]