Question

Determinati numerele naturale a si b asfel incat(a+2)*(b-3)=28

Answer 1

(a+2)=x
b-3=y
x*y=28=> x=1,y=28;x=28,y=1;x=4,y=7;x=7,y=4;x=2,y=14;x=14,y=2(adica divi. lui 28)
a=26,5,2,0,15. b=4,7,10,17,5.

Answer 2

(a+1)*(b-3)=28
a+1=6+1
b-3=7-3
7*4=28

(a+1)*(b-3)=28
a+1=3+1
b-3=10-3
4*7=28

(a+1)*(b-3)=28
a+1=13+1
b-3=5-3
14*2=28

(a+1)*(b-3)=28
a+1=1+1
b-3=17-3
2*14=28
 
(a+1)*(b-3)=28
a+1=0+1
b-3=31-3
1*28=28

(a+1)*(b-3)=28
a+1=27+1
b-3=4-3
28*1=28

Coroniţă+mulţumesc+5 steluţe ? :)