Question

Determinati numerele naturale a si b stiind ca$\frac{1+i}{1-i}$ = a + ib

Answer 1

Amlificand cu1+i, la numarator se obtine (1+i)^2= 1+2i+i^2=1+2i-1=2i, nunitorul va fi (1+i)(1-i) = 1-(i)^2=1-(-1)=2, deci fractia =(2i)/2=i, de unde rezulta a=0; b=1