Question

Determinati numerele naturale ab,stiind ca ba+5(a+2b)=124.

Answer 1

ba+5(a+2b)=124

ba+5a+10b=124

11b+6a=124

6a divizibil cu 2

124 divizibil cu 2

=>11b divizibil cu 2=>b divizibil cu 2

b€{2,4,6,8}

1. b=2

11*2+6a=124

22+6a=124

6a=102

a=17. A

2. b=4

11*4+6a=124

44+6a=124

6a=80. F

3. b=6

11*6+6a=124

66+6a=124

6a=58. F

4. b=8

11*8+6a=124

88+6a=124

6a=36

a=6. A

b€{2;8}

a€{17;6}

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