Question

determinati numerele naturale de 3 cifre scrise ib baza 10 care impartite la 38 dau restul 7​

Answer 1

Răspuns:

a:38=C rest 7=>a=38C+7

numerele cuprinse intre 100 si 999

100 < 38C+7 < 999

100 < 38C+7 => 93 < 38C

999 > 38C+7=> 772 > 38C

93 < 38C < 992

38·3=114 > 100 ; 26·38=988 < 999

C = 3,4,5,6......26

a:38=3 rest 7=>a=38·3+7=>a=121

nr cautate sunt multiplu de 38

121+38=159+38=197.....

numerele in baza 10 sunt: 121,159,197,235,273,311,348,387,425,463,501,539,577,615,653,691,729,

767,805,843,881,919,957,995