Question

Determinati numerele naturale x si y ,astfel incat fractiile urmatoare 2 supra 5, x+2 supra 15 si 10 supra 3y+1 sa fie echivalente

Answer 1

$\frac{2}{5}=\frac{x+2}{15} \\ \\ 5(x+2)=30 \\ \\ x+2=6 \\ \\ x=4 \\ \\ \frac{6}{15}=\frac{10}{3y+1} \\ \\ 6(3y+1)=150 \\ \\ 3y+1=25 \\ \\ 3y=24 \\ \\ y=8$

Answer 2

Salut,

2/5 = (x+2)/15 = 10/(3y+1)

(x+2)/15 = 2/5
5(x+2) = 15•2
5x+10 = 30
5x = 30-10
5x = 20
x = 20/5
x = 4.


2/5 = 10/(3y+1)
2(3y+1) = 10•5
6y+2 = 50
6y = 48
y = 48/6
y = 8.


Succes! :3