Question

Determinati numerele naturale x si y stiind ca x^2×(y+3)=864 Dau coroana

Answer 1

$x,y-\ \textgreater \ apartine.N \\ x^{2} *(y+3)=864=4*216=4*36*6=16*54=9*96=144*6 \\ x^{2}=4,x=2,y+3=216,y=213 \\ x^{2} =36,x=6,y+3=24,y=21 \\ x^{2} =16,x=4,y+3=54,y=51 \\ x^{2} =9,x=3,y+3=96,y=93 \\ x^{2} =144,x=12,y+3=6,y=3 \\ x^{2} =1,x=1,y+3=864,y=861$