Question

Determinati numerele naturale x,y si z daca x+1,y-2 si z+3 sunt direct proportionale cu 2,3 , respectiv 4 si x+y+z=79

Answer 1

(X+1)/2=(y-2)/3=(z+3)/4=k => x=2k-1;; y=3k+2 si z=4k-3 => 9k-2=79 =>9k=81 =>k=9 => x=17; y=29 si z=33