Question

Determinați numerele prime care divid suma a patru puteri consecutive a lui 2

Answer 1

2^n + 2^(n+1) + 2^(n + 2) + 2^(n + 3) = 2^n × (1 + 2 + 2² + 2³) = 2^n × (
3 + 4 + 8) = 2^n × 15 = 2^n × 3 × 5
Numere prime care divid suma sunt: 2, 3 si 5