Question

Determinati numerele rationale pozitive x, y si z care sunt direct proportionale cu numerele 5,6 si 10 iar 2x +3y - 2z= 128

Answer 1

x=5k
y=6k
z=10k
2×5k+3×6k-2×10k=128
10k+18k-20k=128
8k=128
k=16
x=5k=5×16=80
y=6k=6×16=96
z=10k=10×16=160

Answer 2

x supra 5=y supra 6=z supra z=K⇒x=5K,y=6K,z=10K
2X+3Y-2Z=128
2·5k+3·6k-2·10k=128
10k+18k-20k=128
8k=128
k=128:8
k=16
x=5·16=80
y=3·16=48
z=10·16=160
Sper ca te-am ajutat!