Question

determinati numerele rationale x,y z stiind ca sunt direct proportionale cu2,3 ,4 iar 2x+3y-z=27

Answer 1

$\frac{x}{2} = \frac{y}{3}= \frac{z}{4}=K$
$\frac{x}{2}=K$⇒x= 2K
$\frac{y}{3} =K$⇒ y=3K
$\frac{z}{4} =K$⇒ z=4K
2x+ 3y -z = 27
2(2K)+3(3K)-4K=27
4K+9K-4K=27
9K=27⇒k=3
x=2x3=6
y=3x3=9
z=4x3=12