Question

Determinati numerele reale m , stiind ca maximul fuctiei f(x) = mx^2 + (2m - 1) x + m + 1 este 3

Answer 1

a=m

b=2m-1

c=m+1

maxf=-Δ/4a

Δ=b^2-4ac=(2m-1)^2-4m(m+1)=4m^2+1-4m-4m^2+4m=1

maxf=3

3=-1/4m<=>12m=-1=>m=-1/12