Question

Determinați numerele reale ,,x" si ,,y", daca
${x}^{2} + {y}^{2} + 2x - 6y + 10 = 0$

Answer 1

x^2 + 2x + 1 + y^2 -6y +9 = (x+1)^2 + (y-3)^2=0
De aici rezulta ca
x+1=0 => x=-1
y-3=0 => y=3