Question

Determinati numerele reale x si y stiind ca x²+4y²-6x+4y+10=0 . va rog rezolvare completa va rooog

Answer 1

x^2 - 6x  + 9 + 4 y^2+ 4y + 1 = 0
(x - 3 )^2 + 4y^2+4y+1=0

Pt ca sa fie adevarat trebuie ca x=3 si
4y^2+4y+1=0
delta= 4^2-4*4=0
y1=y2= -4/2*4=-1/2

Answer 2

$\Longleftrightarrow (x-3)^2+(2y+1)^2=0\Rightarrow x=3,y=\dfrac{-1}{2}$.