Question

Determinati numerele x,y si z, stiind ca x,y,z sunt direct proportionale cu 1, 3 si respectiv 6 si x+3y-z=48.
Va rog mult

Answer 1

x/1=y/3=z/6=k
x=k, y=3k, z=6k
x+3y-z=48, devine
k+9k-6k=48

4k=48
k=12, deci x=k=12, y=3k=36,  z=6k=6*12=72

x=12, y=36 si y=72

verificare
12+108-72=
120-72=48
48=48

x=12, y=36 si y=72