Question

Determinati numerele x,y,z stiind ca:
a) x/2=y/11=z/7 si x+y+z=80.
b) x/6=y/7=z/8 si x+y+z= 20.
c) x/5=y/3=z/7 si x+y+z=192.
d) x/14=y/11=z/12 si x+y+z=39.

Answer 1

a) x/2=y/11=z/7 si x+y+z=80.
(x+y+z)/2+11+7 =80/20=4
x=8
y=44
z=28
b) x/6=y/7=z/8 si x+y+z= 20.
(x+y+z)/6+7+8 =20/21
x=120/21=40/7
y=140/21=20/3
z=160/21
c) x/5=y/3=z/7 si x+y+z=192.
(x+y+z)/5+3+7 =192/15=64/5
x=64
y=192/5
z=448/5
d) x/14=y/11=z/12 si x+y+z=39.
(x+y+z)/14+11+12 =39/37
x=546/37
y=429/37
z=468/37