Question

Determinati numerele x,y,z,stiind ca:
x supra 2=y supra 11=z supra 7
x+y+z=80

Answer 1

x/2 = y/11 = z/7 = k
x = 2k
y = 11k
z = 7k

x+y+z = 80
2k+11k+7k = 80
20k = 80
k = 4

Atunci:
x = 2k = 8
y = 11k = 44
z = 7k = 28