Question

determinați pe a din [48+50×100÷(28÷a+3×2)-14]×[(50-4×5)+(143-4×6)]=42316

Answer 1

$[48 +50*100:(28:a+6)-14] * [(50 - 4 *5)+(143-4 * 6)]=42316$
$[48 +5000:(28:a+6)-14] *[(50-20)+(143-24)]=42316$
$[48 +5000:(28:a+6)-14] * (30+119)=42316$
$[48 +5000:(28:a+6)-14] * 149=42316$
$48 +5000:(28:a+6)-14=42316:149$
$48 +5000:(28:a+6)-14=284$
$48 +5000:(28:a+6)=284+14$
$48 +5000:(28:a+6)=298$
$5000:(28:a+6)=298-48$
$5000:(28:a+6)=250$
$100:(28:a+6)=250:50$
$100:(28:a+6)=5$
$28:a+6=100:5$
$28:a+6=20$
$28:a=20-6$
$28:a=14$
$a=28:14$
$a=2$