Question

Determinati perechea (a,b) de numerele reale

Answer 1

$\frac{2-i}{3+i}= \frac{(2-i)(3-i)}{(3+i)(3-i)}=\frac{6-2i-3i+i^2}{9-i^2}=\frac{6-5i-1}{9-(-1)}=\frac{5-5i}{10}=\frac{5}{10}-\frac{5i}{10}=\frac{1}{2}-\frac{i}{2}$

$a=\frac{1}{2}$

$b=-\frac{1}{2}$