Question

determinati perechile de nr nat (a,b) pt care are loc egalitatea : a - b supra 2 = 3 supra b+1

Answer 1

(a-b)/2 = 3/(b+1)
(a-b)(b+1)=6
6=1x6
a-b=1
b+1=6
a+1=7
a=6
b=5

6=2x3
a-b=2
b+1=3
a+1=5
a=4
b=2

6=3x2
a-b=3
b+1=2
a+1=5
a=4
b=1

6=6x1
a-b=6
b+1=1
a+1=7
a=6
b=0

Answer 2

2·3=[a-b]·[b+1]
6=[a-b]·[b+1]⇒[a-b]=[1,2,3,6];
⇒[b+1]=[1,2,3,6];⇒toate variantele posibile intre ele[dar corecte];