Question

determinati perechile de numere intregi (a;b) pentru care are loc egalitatea
a-1 supra 13= 1 supra b+1

Answer 1

(a-1)/13=1/(b+1)

(a-1)(b+1)=13=1*13=13*1=(-1)*(-13)=(-13)*(-1)

a-1=1  ...a=2
b+1=13...b=12

a-1=13    a=14
b+1=1     b=0


a-1=-1    a=0
b+1=-13...b=-14


a-1=-13    a=-12
b+1=-1    b=-2

(a;b) ∈{(2;12);(14;0) ;(0;-14);(-12;-2)}