Question

determinati perechile x y de numere intregi pentru care 2(x+2)(y+3)-(x-1)(y×7)=9 va rog mult ajutati.ma

Answer 1

2xy+4y+6x+12-xy-7x+y+7=9
xy+5y-x+10=0
xy+5y-x-5+15=0
(x+5)(y-1)= - 15
Avem ca variante
x+5=-1 siy-1=15 (x, y) =(-6, 16)
x+5=-3 y-1=5 (-8, 6)
x+5=-5 y-1=3 (-10, 4)
x+5= - 15 y-1=1 (-20, 2)
x+5=1 y-1=-15 (-4, - 14)
x+5=3 y-1=-5 (-2, - 4)
x+5=5 y-1= - 3 (0, - 2)
x+5=15 y-1= - 1 (10, 0)