Question

Determinati perechile (x,y) de numere naturale care satisfac egalitatea.

{25-3*[2+(3+x)/3]}*{[6*(y-2)-9]/3-4}=7

Answer 1

{25-3*[2+(3+x)/3]}*{[6*(y-2)-9]/3-4}=7

(25-6-3-x)*(2y-4-3-4)=7
(16-x)*(2y-11)=7
7=1*7
16-x=1  x=15
2y-11=7  y=9


16-x=7  x=9
2y-11=1  y=6