Question

determinati perimetrul triunghiului abc stiind ca ab= 4 dm, masura unghiului a = 60 grade si aria abc= 8 rad 3

Answer 1

A= 1/2*AB*AC*sinA
8√3=1/2*4*AC*sin60°
16√3=4AC*√3/2
16=2AC
AC=8 cm
dupa teorema cosinusului
BC²=AB²+AC²-2AB*AC*cosA
BC²=16+64-2*4*8*1/2
BC²=80-32=48
BC=4√3cm
P=AB+AC+BC=4+8+4√3=12+4√3 (cm)=4(3+√3) (cm)