Question

Determinati primitiv functiei f:R-R f(x)=4x-3 cu proprietatea f(2)=15

Answer 1

cu proprietatea F(2)...etc
F(x) =4*x²/2-3x+C

F(x)=2x²-3x+C
F(2)=2*4-3*2+C=15
8-6+C=15
2+C=15
C=13
F(x)=2x²-3x+13

Answer 2

[tex]F(x)= \int\limits {(4x-3)} \, dx =4\cdot \frac{x^2}{2} -3x+C=2x^2-3x+C\\ F(2)=15\\ F(2)=8-6+C=15=\ \textgreater \ C=13\\ F(x)=2x^2-3x+13[/tex]