Question

Determinati primitiva F a functiei f pentru ca F(1)=2014
3x la a 2-a plus 2x

Answer 1

[tex]\displaystyle \int (3x^2+2x)dx= \displaystyle\int 3x^2 dx+\displaystyle \int 2xdx = x^3+x^2 +C\\ F(x)=x^3+x^2+C\\ F(1)=2014 \\ 2+C=2014\\ C=2012 \Rightarrow \boxed{F(x)=x^3+x^2+2012} [/tex]