Question

determinati raportul atomic raportul de masa si compozitia procentuala pentru trioxid de sulf ,acid fosforic

Answer 1

SO3

raport atomic =>  S:O = 1:3

raport de masa => S:O = 32:16 = 2:1

MSO3 = AS+3AO = 32+3*16 = 32+48 = 80g/mol

%S = 32/80*100 = Calculeaza !!
%O = 48/80*100 = Calculeaza !!

H2SO4

raport atomic => H:S:O = 2:1:4 

raport masic => H:S:O = 2:32:64 = 1:16:32

MH2SO4 = 98g/mol

%H = mH/MH2SO4*100 = 2/98*100 = Calculeaza !!
%S = 32/98*100 =
%O = 64/98*100 =