Question

determinati rezultatul pentru z=2-i impartit la 3i+4

Answer 1

$z=\frac{2-i}{3i+4}=\frac{(3i-4)(2-i)}{(3i+4)(3i-4)}=\frac{6i+3-8+4i}{-9-12i+12i-16}=\frac{-5+10i}{-25}=\frac{1-2i}{5}=\frac{1}{5}-\frac{2}{5}i.$

@robertinnifd