Question

Determinați soluțiile ecuației:
(x-2)²-(x+1)²=x-4

Answer 1

[tex](x-2)^2-(x+1)^2=x-4\\ x^2-4x+4-(x^2+2x+1)=x-4\\ x^2-4x+4-x^2-2x-1=x-4\\ -6x+3=x-4\\ -6x-x=-4-3\\ -7x=-7 ~~|*(-1)\\ 7x=7\\ x= \frac{7}{7} \\ \boxed{x=1}[/tex]

Answer 2

=x²-4x+4 - (x²+2x+1)=x-4
=x²-4x+4-x²-2x-1=x-4
=-6x+3=x-4
=-6x-x=-7
=-7x=-7
x=7/7 =1