Question

Determinați soluțiile ecuațiilor:
b)(x-2)²-(x+1)²=x-4
AJUTOR

Answer 1

${(x - 2)}^{2} - {(x + 1)}^{2} = x - 4$

${x}^{2} - 4x + 4 - ( {x}^{2} + 2x + 1) = x - 4$

${x}^{2} - 4x + 4 - {x}^{2} - 2x - 1 = x - 4$

$- 4x - 2x - x = - 4 - 4 + 1$

$- 7x = - 7 \: | \div ( - 7)$

$x = 1$

Answer 2

(x-2)²-(x+1)² = x-4
(x-2-(x+1))•(x-2+x+1) = x-4
(x-2-x-1)•(2x-1) = x-4
-3•(2x-1) = x-4
-6x+3 = x-4
-7x = -7
x = 1