Question

Determinati solutiile x∈R ale ecuatiilor urmatoare: a) x²=2·2²·$2^{2}$²:[2+2²+$2^{2}$²:($2^{2}$²-2²·2)] Rezolvati-mi va rogg!!

Answer 1

2^2^2/[2+2^2+2^2^2/(2^2^2-2^2·2)]=16/(6+16/8)=16/(6+2)=16/8= 2
2*2^2=8

x²=8*2=16 => x^2=16 => x= ±4