Question

Determinati suma cifrelor numerelor a) 5 la puterea 2011 × 16 la puterea503 b)50 la puterea 20 × 2 la puterea 28 !!!rapid pls

Answer 1

5²⁰¹¹ × 16⁵⁰³ =
=5²⁰¹¹ × 2²⁰¹² =
=5²⁰¹¹ × 2²⁰¹¹ ×2=
=10²⁰¹¹ ×2=2 urmat de 2011 zerouri
deci suma cifrelor e 2+2011×0=2

b)50²⁰× 2²⁸=
=(5²×2)²⁰× 2²⁸=
=5⁴⁰×2²⁰× 2²⁸=
=5⁴⁰×2⁴⁰× 2⁸=
=10⁴⁰× 256=256 urmat de 40 de zerouri
suma cifrelor este 2+5+6+40×0=13