Question

Determinati termenu I necunoscut x [25-(2-3)²]:3² = 2^x
va roog am nevoie rapidddd​

Answer 1

Răspuns:

[25-($1^{2}$)]: $3^{2} = 2^{x}$

(25-1):$3^{2} =2^{x}$

24:$3^{2} =2^{x}$

$\frac{24}{3^{2} }$=$2^{x}$

$\frac{24}{9} =2^{x}$

$\frac{8}{3}=2^{x}$

$x=3-$$log_{2} (3)$