Question

determinati termenul necunoscut x, stiind că : (2^3×3^5)^2÷(2^4×3^6)÷3^2=6^x

Answer 1

[tex](2^3*3^5)^2:(2^4*3^6):3^2=6^x [/tex]
$(2^3*3^5)^2:(3^2*6^4)* \frac{1}{3^2} =6^x$
$(2^3*3^5)^2:(9*6^4)* \frac{1}{3^2} =6^x$
$\frac{(2^3*3^5)^2}{9*6^4} = \frac{1}{3^2} = 6^x$

(3^2*6^3)^2/3^2*3^4*2^4 *1/3^2=6^x
3^4*2^6*3^6/3^2*3^4*2^4 *1/3^2 = 6^x
2^2*3^4*1/3^2=6^x
2^2*3^2=6^x
(2*3)^2=6^x
6^2=6^x
6^x=6^2
x=2