Question

determinati toate numerele naturale care impartite la 6 dau catul 13.

Answer 1

1) Numerele sunt  

13*6+0=78

13*6+1=79

13*6+2=80

13*6+3=81

13*6+4=82

13*6+5=83

Answer 2

D : I = C (rest R <I)

=> D : 6 = 13 (R=0;1;2;3;4;5)  adica: D=13*6+R = 78+ ,, R "

D = {78; 79; 80; 81; 82; 83}