Question

Determinati toate numerele naturale de forma abc , stiind ca 200< abc <400 si c=a+b+3

Answer 1

Răspuns:

Explicație pas cu pas:

200< abc <400 ;  c=a+b+3

<=> abc ∈ (200 , 400) =>

a = 2 , 3

a = 2 => c = 2 + b + 3

b = 0 => c = 5

b = 1 => c = 6

b = 2 => c = 7

b = 3 => c = 8

b = 4 => c = 9

205 ; 216 ; 227 ; 238 ; 249

a = 3  => c = 3 + b + 3

b = 0 => c = 6

b = 1 => c = 7

b = 2 => c = 8

b = 3 => c = 9

306 ;317 ; 328 ; 339

Answer 2

Răspuns:

200< abc <400

c=a+b+3

a=2; b=0,1,2,3,4; c=5,6,7,8,9

a=2=>b=0=>c=5

a=2=>b=1=>c=6

a=2=>b=2=>c=7

a=2=>b=3=>c=8

a=2=>b=4=>c=9

a=3 ; b=0,1,2,3 ;c=6,7,8,9

a=3=>b=0=>c=6

a=3=>b=1=>c=7

a=3=>b=2=>c=8

a=3=>b=3=>c=9

abc={205,216,227,238,249,306,317,328,339}