Question

Determinati toate numerele naturale de forma:x14x 3xx xxx 2x5y xy divizibile cu doi HELP

Answer 1

un nr.se divide cu 2 daca ultima cifra a nr.este para, deci 0,2,4,6,8
x14x dam valori lui x
deci nr.care se divid cu 2 sunt:1140,1142,1144,1146,1148,2140,2142,2144,2146,2148,3140,3142,3144,3146,3148,4140,4142,4144,4146,4148,5140,5142,5144,5146,5148,6140,6142,6144,6146,6148,7140,7142,7144,7146,7148,8140,8142,8144,8146,8148,9140,9142,9144,9146,9148
 3xx ⇒300,322,344,366,388
xxx⇒ 222,444,666,888
 2x5y ⇒2150,2152,2154,2156,2158,2250,2252,2254,2256,2258,2350,2352,2354,2356,
2358,,2450,2452,2454,2456,2458,2550,2552,2554,2556,2558,2650,2652,2654,2656,
2658,2750,2752,2754,2756,2758,2850,2852,2854,2856,2858,2950,2952,2954,2956,
2958
xy⇒ 10,12,14,16,18,20,22,⇒24,26,28,30..................98