Question

determinati toate numerele scrise in baza 10 de forma ab care sunt cu 36 mai mari decat form ba

Answer 1

ab=36+ba

10a+b=36+10b+a

10a-a+b-10b=36

9a-9b=36

9(a-b)=36

a-b=4

(a,b)∈{(5,1), (6,2), (7,3), (8,4), (9,5)}

ab∈{51, 62, 73, 84, 95}