Question

Determinați trei numere naturale direct proporționale cu 2 ,5 si 6 asfel incat 2a+3b +c=500​

Answer 1

Salut!

a/2=b/5=c/6=k

a=2k

b=5k

c=6k

2a+3b+c=500

2x2k+3x5k+6k=500

4k+15k+6k=500

25k=500

k=20

a=40

b=100

c=120

Succes!

Answer 2

{a, b, c} d. p. {2,5,6} -> a/2=b/5=c/6=k

a/2=k - > a=2k

b/5=k - > b=5k

c/6=k - > c=6k

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2a+3b+c=500

2*2k+3*5k+6k=500

4k+15k+6k=500

25k=500

k=20

a=2k

a=20

b=5k

b=100

c=6k

c=120