Question

determinati trei numere stiind ca daca se calculeaza mediile aritmetice a cate doua dintre aceste numere se obtin valorile 32, 39 si 41

Answer 1

(a+b)/2=32      a+b=64
(a+c)/2=39      a+c=78
(b+c)/2=41      b+c=82
                  a+b+a+c+b+c=64+78+82
                  2(a+b+c)=224
                     a+b+c=224:2
                    a+b+c=112 
a=112-82=30
b=112-78=34
c=112-64=48

Answer 2

Fie a, b, c cele4 3 numere

atunci

a+b=2*32

b+c=2*39

c+a=2*41

le adunam pe toate

2(a+b+c)=2(32+41+39)

a+b+c=112

dar a+b=2*32=64

deci c=112-64=48

dar b+c=2*39=78

deci a=112-78=34

dar c+a=2*41=82

deci b=112-82=30

a=34;b=30;c=48 care verrifica datele problemei