Question

Determinati un punct ce apartine graficului functiei f:R =>R,f(x)=-4x-4 , stiind ca abscisa este 38%din ordonata

Answer 1

$f(x)=-4x-4\\A(x_A, y_A)\in G_f\text{ astfel \^inc\^at }x_A=38\%\text{ din }y_A\\\Leftrightarrow x_A=\displaystyle\frac{38}{100}f(x_A)=\frac{38}{100}(-4x_A-4)\Leftrightarrow 100x_A=-152x_A-152\\252x_A=-152\Rightarrow x_A=-\frac{38}{63}\\y_A=f(x_A)=-4\cdot\left(-\frac{38}{63}\right)-4=-\frac{100}{63}\\\Rightarrow A\left(-\frac{38}{63},-\frac{100}{63}\right)$