Question

Determinați valoarea lui a din:
{[(205:5+362:2)—32*6+a]*221:13}—140:5=635
[(30+226:2+a:4):29+20*100]:5—11*6—5*67=0

Answer 1

Ex.1. [(41+181)-(192+a)*221:3]-28=635 / +28 [222-(192+a)*221:3=663 / 3 [222-(192+3)*221=1989 /:221 [222-(192+a)=9 /-222 192+a=213 /-192 a=21 Ex2.[(30+113+a:4):29+2000]:5-66-335=0 [(143+a:4):29+2000]:5-66=335 [(143+a:4):29+2000]:5=401 /*5 (143+a:4):29+2000=2005 /-2000 (143+a:4):29=5 /*29 143+a:4=145 143+a=680 a=537