Question

Determinati valoarea lui a din: [48+50×100(28:a+3×2)-14]×[(50-4×5)+(143-4×6)]=42316

Answer 1

[48+50×100(28:a+3×2)-14]×[(50-4×5)+(143-4×6)]=42316

[48+5000(28:a+6)-14]×[(50-20)+(143-24)]=42316

[48+5000(28:a+6)-14]×(30+119) = 42316

[48+5000(28:a+6)-14] × 149 = 42316

[48+5000(28:a+6)-14] = 42316 : 149

48+5000(28:a+6)-14 = 284

5000(28 : a + 6) = 284 - 48 + 14

5000(28 : a + 6) = 250

28 : a + 6 = 5000 : 250

28 : a + 6 = 20

28 : a = 20 - 6

28 : a = 14

a = 28 : 14

a = 2
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