Question

determinati valorile lui a din: {[(205:5+362:2)-32x6+a]x221:13}-140:5=635

[(30+226:2+a:4):29+20x100]:5-11x6-5x67=0

Answer 1

{[(41+181)-192+a]x17}-28=635
[(222-192+a)x17]-28=635
[(30+a)x17]-28=635
(30+a)x17=635+28
(30+a)x17=663
30+a=663:17
30+a=39
a=39-30
a=9

[(30+113+a:4):29+2000]:5-66-335=0
[(143+a:4):29+2000]:5=335+66
[(143+a:4):29+2000]:5=401
(143+a:4):29+2000=401x5
(143+a:4):29+2000=2005
(143+a:4):29=2005-2000
(143+a:4):29=5
143+a:4=29x5
143+a:4=145
143+a=145x4
143+a=580
a=580-143
a=437