Matematică, întrebare adresată de calinovidiu15, 8 ani în urmă

Determinati x ∈ (0,\frac{\pi }{2})

Stiind ca \frac{3sin x + cos x}{sinx} = 4


Darrin2: sinx-cosx=0=>tgx=1=> x=pi/4
albatran: salut, data la BAC sub I,,recent

Răspunsuri la întrebare

Răspuns de tcostel
2

 

\displaystyle\bf\\x\in\Big(0,~\frac{\pi}{2}\Big)\\\\sau\\\\x\in\Big(0,~90^o\Big)\\\\\\\frac{3sin\,x+cos\,x}{sin\,x}=4\\\\\\\frac{3sin\,x}{sin\,x}+\frac{cos\,x}{sin\,x}=4\\\\\\3+\frac{cos\,x}{sin\,x}=4\\\\\\\frac{cos\,x}{sin\,x}=4-3\\\\\\\frac{cos\,x}{sin\,x}=1\\\\\\ctg\,x=1\\\\\\x=arcctg(1)=\frac{\pi}{4}=45^o\\\\\\\boxed{\bf~x=\frac{\pi}{4}}\\\\ sau\\\\\boxed{\bf~x=45^o}

 

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