Question

Determinati x din egalitățiile:
a) 7 supra 18 + 5 supra 18 - x supra 18 = 2 supra 18
b) 7 supra 21 + 3 supra 21 - x supra 21 =2 supra 21
c) 1 - x supra 19 = 6 supra 19
Vă rog ajutoor!

Answer 1

c) [tex] \frac{1-x}{19}= \frac{6}{19}

  x= - \frac{5}{19} [/tex]

b) [tex] \frac{7+3-x}{21} = \frac{2}{21}

  \frac{10-x}{21} = \frac{2}{21}

x= \frac{8}{21}

  a) [/tex][tex] \frac{7+5-x}{18} = \frac{2}{18}

  \frac{12-x}{18} = \frac{2}{18}

x= \frac{10}{18} [/tex]

Answer 2

a)$\frac{7}{18} + \frac{5}{18} - \frac{x}{18}= \frac{2}{18}$
$\frac{12}{18}- \frac{x}{18}= \frac{2}{18}$
$\frac{x}{18}= \frac{12}{18}- \frac{2}{18}$
$\frac{x}{18}= \frac{10}{18} =\ \textgreater \ x=10$

b)$\frac{7}{21} + \frac{3}{21}- \frac{x}{21}= \frac{2}{21}$
$\frac{10}{21}- \frac{x}{21} = \frac{2}{21}$
$\frac{x}{21}= \frac{10}{21}- \frac{2}{21}$
$\frac{x}{21}= \frac{8}{21}=\ \textgreater \ x=8$

c)$\frac{1-x}{19}= \frac{6}{19}$
[tex]=\ \textgreater \ 1-x=6 \\ x=1-6 \\ x=-5[/tex]

Verificare(c): 1-x=6=1-(-5)=6 =1+5=6.

                                      ~Sper ca te-am ajutat!~