Question

Determinati x si y daca 4x^2-4x+y^2-4y+5=0

Answer 1

4 x^{2} -4x+1 + y^{2}-4y+4=0 =>
(x -2) ^{2} + (y-2)^{2}=0 =>
x=y[/tex]
X=Y=2.
Ce am facut? L-am scris pe 5=4+1, apoi am format patrate. O suma de patrate, trebuie sa stii ca e 0, cand fiecare patrat este zero, astfel x-2=0 si ... Inteles?

Answer 2

$4x^{2} -4x+1+ y^{2} -4y+4=0$
$(2x-1)^{2} +(y-2)^{2} =0$⇔$(2x-1)^{2} =0$⇔2x-1=0⇔x=1/2
$(y-2)^{2} =0$⇔y=2