Question

Determinatil pe x din:. 5×{16+[25-(12:x:2)×9]:8}:9=10

Answer 1

[tex]5\cdot\{16+[25-(12:x:2)\cdot9]:8\}:9=10\\ \{16+[25-(12:x:2)\cdot9]:8\}:9=10:5=2\\ 16+[25-(12:x:2)\cdot9]:8=2\cdot9=18\\ {}[25-(12:x:2)\cdot9]:8=18-16=2\\ 25-(12:x:2)\cdot9=2\cdot8=16\\ -(12:x:2)\cdot9=16-25=-9\\ (12:x:2)\cdot9=9\\ 12:x:2=9:9=1\\ 12:x=1\cdot2=2\\ x=12:2=6[/tex]